Create a random array of n integers. Accept a value x from user and use linear search algorithm to check whether the number is present in the array or not and output the position if the number is present.

Linear Search:

Write a c program to generate random array of n integers and apply linear search to find value entered by user.

  • Linear Search Algorithm:

Step 1: Start

Step 2: Accept n numbers in an array num and a number to be searched

Step 3: se ti=0 and flag=0

Step 4: if i<n then goto next step else goto step 7

Step 5: Compare num[i] and number

If equal then

set flag=1 and goto step 7

Step 6: i=i+1 and goto step 4

Step 7: if (flag=1) then

Print “Required number is found at location i+1”

else

Print “Require data not found”

Step 8: Stop

  • Time Complexity:

Base Case: O(1) 
Worst Case: O(n) 
Average Case: O(n)


  • Create a random array of n integers. Accept a value x from user and use linear search algorithm to check whether the number is present in the array or not and output the position if the number is present.

#include<stdio.h>
#define max 10

int main()
{
int a[max],k,i,n,flag=0,index;
printf("Enter n:");
scanf("%d",&n);

generate(a,n);
printf("Random elements are\n");
   for(i=0;i<n;i++)
      printf("%d\n",a[i]);

printf("Enter number to search: ");
   scanf("%d",&k);
linearsearch(a,n,k);
}
void generate(int a[],int n)
{
int i;
for(i=0;i<n;i++)
   a[i]=rand()%100;

}
void linearsearch(int a[],int n,int k)
{
int i,flag=0,index ;
for(i=0;i<n;i++)
if(a[i]==k)
{
flag=1;
index=i;
}
if(flag==1)
{
printf("Element found at index %d",index+1);
}
else
printf("Not Found");
}

Output :

Enter n:6
Random elements are
41
67
34
0
69
24
Enter number to search: 34
Element found at index 3
Process returned 0 (0x0)   execution time : 6.261 s
Press any key to continue.

Post a Comment

0 Comments